Load Data A Single span beam
P1DL kips L
P1LL kips a
P2DL kips b
P2LL kips
DL kips / ft.
LL kips / ft.
Dead Weight of Beam = 0.52 kips/ft
total factored Point Load 1 = 0.00 kips
total factored Point Load 2 = 0.00 kips
total factored Uniform Load = 0.72 kips
VA = #DIV/0! kips
VB = #DIV/0! kips
Max. Shear = #DIV/0! kips
Max. ultimate positive moment = #DIV/0! kips.ft
Max. ultimate negative moment = 0 kips.ft
hmin = 0 inches
req’ d = #DIV/0! inches
Determine depth (d) and thickness (h)
Use Beam Depth = #DIV/0! inches Thickness =
Check the beam weight by recalculating the load ……. Passed
Determine As
req’ As = #DIV/0! inches.2
Bar No. 5 6 7 8
Area / bar (in2) 0.31 0.44 0.6 0.79
No. of bars* #DIV/0! #DIV/0! #DIV/0! #DIV/0!
Min. number of 2 steel bars is required
Use the top bar = 2 No. 14 bar Use the bottom bar size =Check Shear
Check if Bd(f’c)1/2 > Vmax / f
The shear reinforcement is #DIV/0!
Bar No. 3 4 5
Area (in2) 0.22 0.4 0.62
Spacing of bars #DIV/0! #DIV/0! #DIV/0!
